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double foo(int n)
{
int i;
double sum;
if(n == 0)
{
return 1.0;
}
else
{
sum = 0.0;
for(i = 0; i < n; i++)
{         
sum += foo(i);
}
return sum;
}
}
The space complexity of the above code is?
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
double foo(int n){int i;double sum;if(n == 0){return 1.0;}else{sum = 0...
Note that the function foo() is recursive. Space complexity is O(n) as there can be at most O(n) active functions (function call frames) at a time. 
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